How do you find the x and y intercepts for $7 x + 8 y = 18$ $7x + 8y = 18$ ?

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Answer 1 · 2018-05-01T12:37:47

$:. y$ -intercept = $18/8$

$:. x$ -intercept = $18/7$

$x$ -intercept means the point where the lines reaches the $x$ -axis which means $y=0$

$y$ -intercept means the point where the lines reaches the $y$ -axis which means $x=0$

To find $y$ -intercept, there is also another method which is by using the formulae itself, which is $y=mx+c$ where $c$ stands for $y$ -intercept.

Regarding your question, to find $y$ -intercept using
[ $y=mx+c$ method]

$=> 7x + 8y = 18$

$=> y = (18-7x)/8$

$=> y = (18)/8 - (7x)/8$

$=> y = -(7x)/8 + (18)/8$

$:. y$ -intercept = $18/8$

Or apply $x=0$

$=> 8y = 18$

$:. y$ -intercept = $18/8$

To find $x$ -intercept, apply $y=0$

$=> 18/8 = (7x)/8$

$=> 144 = 56x$

$:. x$ -intercept = $18/7$

How do you find the x and y intercepts for 7x + 8y = 187x+8y=187x + 8y = 18?