How do you find the x and y intercepts for a line that goes through (2,1) and (6,4)?

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Answer 1 · 2018-04-10T17:04:08

I'm assuming this is a straight line.

Find the equation of the line. First, find the gradient.

#(4-1)/(6-2) = 3/4#

Then substitute values into the equation #y-y1 = m(x-x1)#. I'm going to use (2,1).

#y - 1 = 3/4(x-2)#

#y-1=3/4x-1.5#
#y=3/4x-0.5#

Now you know the y-intercept from the equation: #(0,-0.5)#

Now, substitute #y=0# into the equation to find the x-intercept

#0 = 3/4x-0.5#
#3/4x=0.5#
#x=2/3#

The x-intercept is #(2/3,0)#