How do you find the x and y intercepts for $R (x) = \frac{3 x}{x^{2} - 9}$ $R(x) = (3x) / (x^2 - 9)$ ?

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How do you find the x and y intercepts for $R (x) = \frac{3 x}{x^{2} - 9}$ $R(x) = (3x) / (x^2 - 9)$ ?

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Answer 1 · 2017-03-15T09:07:05

$both intercepts = 0$ $"both intercepts "=0$

Explanation:

To find the intercepts.

$∙ substitute x = 0, in R(x), for y- intercept$ $• " substitute x = 0, in R(x), for y- intercept"$

$∙ substitute y = 0, in R(x), for x-intercept$ $• " substitute y = 0, in R(x), for x-intercept"$

$x = 0 \to R (0) = \frac{0}{0 - 9} = \frac{0}{- 9} = 0 \leftarrow y-intercept$ $x=0toR(0)=0/(0-9)=0/(-9)=0larrcolor(red)" y-intercept"$

The denominator of R(x) cannot be zero as this would make R(x) undefined. The numerator can, however, equal zero.

$y = 0 \to 3 x = 0 \to x = 0 \leftarrow x-intercept$ $y=0to3x=0tox=0larrcolor(red)" x-intercept"$

That is R(x) passes through the origin (0 ,0)
graph{(3x)/(x^2-9) [-10, 10, -5, 5]}

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How do you find the x and y intercepts for $R (x) = \frac{3 x}{x^{2} - 9}$ $R(x) = (3x) / (x^2 - 9)$ ?

1 Answer

Explanation:

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How do you find the x and y intercepts for R(x) = (3x) / (x^2 - 9)R(x)=3xx2−9R(x) = (3x) / (x^2 - 9)?

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How do you find the x and y intercepts for $R (x) = \frac{3 x}{x^{2} - 9}$ $R(x) = (3x) / (x^2 - 9)$ ?