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How do you find the x and y intercepts for $x - 2 y = 8$ $x - 2y = 8$ ?

1 Answer

Dec 4, 2015

To find the x-intercept set $y = 0$ $y=0$ in the equation and solve for $x$ $x$ .

To find the y-intercept set $x = 0$ $x=0$ in the equation and solve for $y$ $y$

Explanation:

Using the given equation $x - 2 y = 8$ $x-2y=8$ as an example:

Setting $y = 0$ $color(red)(y=0)$
$XXX x - 2 \times 0 = 8$ $color(white)("XXX")x-2xxcolor(red)(0) = 8$
$XXX x = 8$ $color(white)("XXX")x=8$
The x-intercept is $8$ $8$

Setting $x = 0$ $color(blue)(x=0)$
$XXX 0 - 2 y = 8$ $color(white)("XXX")color(blue)(0)-2y=8$
$XXX - 2 y = 8$ $color(white)("XXX")-2y=8$
$XXX y = - 4$ $color(white)("XXX")y=-4$
The y-intercept is $(- 4)$ $(-4)$

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