How do you find the x and y intercepts for $y = \frac{2}{3} x + 4$ $y= 2/3x + 4$ ?

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How do you find the x and y intercepts for $y = \frac{2}{3} x + 4$ $y= 2/3x + 4$ ?

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Answer 1 · 2018-06-17T15:26:39

$x = - 6$ $x=-6$
$y = 4$ $y=4$

Explanation:

To find the x-intercept, substitute $y = 0$ $y=0$ into the equation (as the graph crosses the x-axis when y is zero).

$0 = \frac{2}{3} x + 4$ $0=2/3x+4$
$\frac{2}{3} x = - 4$ $2/3x=-4$
$x = - \frac{4}{\frac{2}{3}}$ $x=-4/(2/3)$
$x = - 4 \cdot (\frac{3}{2})$ $x=-4*(3/2)$
$x = - 6$ $x=-6$

Similarly, to find the y-intercept, substitute $x = 0$ $x=0$ into the equation.

$y = \frac{2}{3} \cdot 0 + 4$ $y=2/3*0+4$
$y = 4$ $y=4$

Hope this helps :)

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How do you find the x and y intercepts for $y = \frac{2}{3} x + 4$ $y= 2/3x + 4$ ?

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How do you find the x and y intercepts for $y = \frac{2}{3} x + 4$ $y= 2/3x + 4$ ?