How do you find the x and y intercepts for $y = 3 x + 1$ $y=3x+1$ ?

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Answer 1 · 2015-11-27T21:38:29

$x$ $x$ intercept is at $x = - \frac{1}{3}$ $x=-1/3$ and $y$ $y$ intercept is at $y = 1$ $y=1$

The intercept for the y-axis has to be when $x = 0$ $x=0$
The intercept for the x-axis has to be when $y = 0$ $y=0$

$To find the y intercept$ $color(blue)("To find the y intercept")$
so substitute 0 for $x$ $x$ in the equation giving:

$y = (3 \times 0) + 1$ $y=(3xx0)+1$

$y = 1$ $y=1$

$To find the x intercept$ $color(blue)("To find the x intercept")$
Substitute 0 for $y$ $y$ in the equation giving:

$0 = 3 x + 1$ $0=3x+1$

Subtract 1 from both sides

$0 - 1 = 3 x + 1 - 1$ $0-1 =3x+1-1$

$3 x = - 1$ $3x=-1$

Divide both sides by 3

$\frac{3 x}{3} = - \frac{1}{3}$ $(3x)/3=-1/3$

$x = - \frac{1}{3}$ $x=-1/3$

How do you find the x and y intercepts for y=3x+1y=3x+1?