How do you find the x and y intercepts for $y = 3 x + 2$ $y=3x+2$ ?

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How do you find the x and y intercepts for $y = 3 x + 2$ $y=3x+2$ ?

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Answer 1 · 2018-04-13T15:01:36

The $y$ $y$ -intercept is $2$ $2$
The $x$ $x$ -intercept is $- \frac{2}{3}$ $-2/3$

Explanation:

Since $y = 3 x + 2$ $y=3x+2$ is in the form $y = m x + b$ $y=mx+b$ , the $y$ $y$ -intercept must be $b$ $b$ , or $2$ $2$ . To find the $x$ $x$ -intercept, set $y$ $y$ to $0$ $0$ .
$0 = 3 x + 2$ $0=3x+2$ Isolate $x$ $x$ and its coefficient.
$3 x = - 2$ $3x=-2$ Isolate $x$ $x$
$x = - \frac{2}{3}$ $x=-2/3$
Therefore the $x$ $x$ -intercept is $- \frac{2}{3}$ $-2/3$

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How do you find the x and y intercepts for $y = 3 x + 2$ $y=3x+2$ ?

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How do you find the x and y intercepts for y=3x+2y=3x+2?

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How do you find the x and y intercepts for $y = 3 x + 2$ $y=3x+2$ ?