How do you find the x and y intercepts for $y = - \frac{6}{5} x + 6$ $y= - 6/5x + 6$ ?

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Answer 1 · 2018-03-25T05:13:39

$x$ $x$ -intercept at 5,
$y$ $y$ -intercept at -6.

Since this is a linear function with a $b$ $b$ -value and a slope, it must cross the $x$ $x$ and $y$ $y$ axes at some point.

To solve for the $y$ $y$ -intercept, let $x$ $x$ = $0$ $0$ :

$y$ $y$ = $- (\frac{6}{5})$ $-(6/5)$ ( $0$ $0$ )+6
$y$ $y$ = 6

To solve for the $x$ $x$ - intercept, let $y$ $y$ = $0$ $0$ :

$0$ $0$ = $- (\frac{6}{5}) (x)$ $-(6/5)(x)$ +6
$- 6 = - (\frac{6}{5}) (x)$ $-6=-(6/5)(x)$
$- 30 = - 6 x$ $-30=-6x$
$x = 5$ $x=5$

How do you find the x and y intercepts for y=−65x+6y= - 6/5x + 6?