How do you find the x and y intercepts for y = -|x+10|y=|x+10|?

1 Answer
Mar 29, 2018

General shape is ^^^

y_("intercept")->(x,y)=(0,-10)yintercept(x,y)=(0,10)

x_("intercept")->(x,y)=(10,0)xintercept(x,y)=(10,0)

Vertex ->(x,y)=(-10,0)(x,y)=(10,0)

Explanation:

color(blue)("Tip 1: Shape of the graph")Tip 1: Shape of the graph

If an absolute is positive we get the shape vvv

If an absolute is negative we get the shape ^^^color(red)( larr" Our one") Our one

This follows the same pattern as with a quadratic.

If the x^2x2 term is positive we get uuu

If the x^2x2 term is negative we get nnn
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
color(blue)("Tip 2: horizontal position")Tip 2: horizontal position

If you add a value to the xx then it moves the graph left
If you subtract a value from the xx then it moves the graph right

Example: suppose we had say

y=x^2+2x-2y=x2+2x2
then we dicide to change it so that we add 4 to xx. We have:

y=(x+4)^2+2(x+4)-2y=(x+4)2+2(x+4)2

Because we have added 4 it moves the graph y=x^2_2x-2y=x2_2x2 left by 4

color(red)("Our one:")Our one:
So if we add 10 to y=-|x|y=|x| giving y=-|x+10|y=|x+10| we move the graph of y=-|x|y=|x| left by 10
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
color(blue)("Tip 3: x-intercept")Tip 3: x-intercept

The graph crosses the x-axis at y=0y=0

y=-|x+10| color(white)("d")-> color(white)("d") 0=-|x-10|y=|x+10|dd0=|x10|

The only way we can obtain 0 as the value of yy is if x=+10x=+10

So we have: x_("intercept")->(x,y)=(10,0)xintercept(x,y)=(10,0)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
color(blue)("Tip 4: y-intercept")Tip 4: y-intercept

The graph crosses the y-axis at x=0x=0

y=-|0+10| = -10y=|0+10|=10

So we have: y_("intercept")->(x,y)=(0,-10)yintercept(x,y)=(0,10)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
color(blue)("Tip 4: The vertex")Tip 4: The vertex

This occurs when the overall value color(red)("within")within the absolute is about to 'flip' sign from positive to negative. That is, it becomes 0 which happens at x=-10x=10

y=-|color(magenta)(x)+10|y=|x+10|

color(limegreen)(y)=-|ubrace(color(magenta)(-10)+10)| = color(limegreen)(0)
color(white)("ddddddddd")darr
color(white)("dddddddd.d")0

Vertex ->(x,y)=(color(magenta)(-10),color(limegreen)(0))

Tony B