How do you find the x and y intercepts for $y = x - 2$ $y=x-2$ ?

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How do you find the x and y intercepts for $y = x - 2$ $y=x-2$ ?

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Answer 1 · 2017-01-23T03:43:45

The y-intercept is $- 2$ $-2$ and the point is $(0, - 2)$ $(0,-2)$ .

The x-intercept is $2$ $2$ , and the point is $(2, 0)$ $(2,0)$ .

Explanation:

$y = x - 2$ $y=x-2$ is in point-slope form $y = m x + b$ $y=mx+b$ , where $m$ $m$ is the slope and $b$ $b$ is the y-intercept. The y-intercept is the value of $y$ $y$ when $x$ $x$ is $0$ $0$ .

For $y = x - 2$ $y=x-2$ , the y-intercept is $- 2$ $-2$ and the point is $(0, - 2)$ $(0,-2)$ .

To find the x-intercept, make $y$ $y$ equal to zero and solve for $x$ $x$ .

$0 = x - 2$ $0=x-2$

Add $2$ $2$ to both sides.

$2 = x$ $2=x$

The x-intercept is $2$ $2$ , and the point is $(2, 0)$ $(2,0)$ .

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How do you find the x and y intercepts for $y = x - 2$ $y=x-2$ ?

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How do you find the x and y intercepts for $y = x - 2$ $y=x-2$ ?