How do you find the x and y intercepts of $2.5 x - 5 y = - 15$ $2.5x-5y=-15$ ?

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Answer 1 · 2017-02-15T20:42:07

see the entire solution process below:

To find the y-intercept, set $x = 0$ $x = 0$ and solve for $y$ $y$ :

$(2.5 \times 0) - 5 y = - 15$ $(2.5 xx 0) - 5y = -15$

$0 - 5 y = - 15$ $0 - 5y = -15$

$- 5 y = - 15$ $-5y = -15$

$\frac{- 5 y}{- 5} = - \frac{15}{- 5}$ $(-5y)/color(red)(-5) = -15/color(red)(-5)$

$(color(red)(cancel(color(black)(-5)))y)/cancel(color(red)(-5)) = 3$

$y = 3$

The y-intercept is $3$ or $(0, 3)$

To find the x-intercept, set $y = 0$ and solve for $x$ :

$2.5x - (5 xx 0) = -15$

$2.5x - 0 = -15$

$2.5x = -15$

$(2.5x)/color(red)(2.5) = -15/color(red)(2.5)$

$(color(red)(cancel(color(black)(2.5)))x)/cancel(color(red)(2.5)) = -6$

$x = -6$

The x-intercept is $-6$ or $(-6, 0)$

How do you find the x and y intercepts of 2.5x-5y=-152.5x−5y=−152.5x-5y=-15?