How do you find the x and y intercepts of $2 x - 3 y = - 12$ $2x-3y= -12$ ?

Question

1537 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-22T20:40:39

See the entire solution process below:

To find the x-intercept by substitution set $y = 0$ $y = 0$ and solve for $x$ $x$ :

$2 x - (3 \times 0) = - 12$ $2x - (3 xx 0) = -12$

$2 x - 0 = - 12$ $2x - 0 = -12$

$2 x = - 12$ $2x = -12$

$\frac{2 x}{2} = - \frac{12}{2}$ $(2x)/color(red)(2) = -12/color(red)(2)$

$(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = -6$

$x = -6$ for $y = 0$ therefore the x-intercept is $-6$ or $(-6, 0)$

To find the y-intercept by substitution set $x = 0$ and solve for $y$ :

$(2 xx 0) - 3y = -12$

$0 - 3y = -12$

$-3y = -12$

$(-3y)/color(red)(-3) = (-12)/color(red)(-3)$

$(color(red)(cancel(color(black)(-3)))y)/cancel(color(red)(-3)) = 4$

$y = 4$ for $x = 0$ therefore the y-intercept is $4$ or $(0, 4)$

How do you find the x and y intercepts of 2x-3y= -122x−3y=−12 2x-3y= -12?