How do you find the x and y intercepts of $2 x - 6 y = - 12$ $2x-6y=-12$ ?

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Answer 1 · 2017-04-15T13:36:26

See the entire solution process below:

x- intercept)

Set $y$ $y$ equal to $0$ $0$ and solve for $x$ $x$ :

$2 x - 6 y = - 12$ $2x - 6y = -12$ becomes:

$2 x - (6 \cdot 0) = - 12$ $2x - (6 * 0) = -12$

$2 x - 0 = - 12$ $2x - 0 = -12$

$2 x = - 12$ $2x = -12$

$\frac{2 x}{2} = - \frac{12}{2}$ $(2x)/color(red)(2) = -12/color(red)(2)$

$(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = -6$

$x = -6$

The x-intercept is $-6$ or $(-6, 0)$

y- intercept)

Set $x$ equal to $0$ and solve for $y$ :

$2x - 6y = -12$ becomes:

$(2 * 0) - 6y = -12$

$0 - 6y = -12$

$-6y = -12$

$(-6y)/color(red)(-6) = (-12)/color(red)(-6)$

$(color(red)(cancel(color(black)(-6)))y)/cancel(color(red)(-6)) = 2$

$y = 2$

The y-intercept is $2$ or $(0, 2)$

How do you find the x and y intercepts of 2x-6y=-122x−6y=−122x-6y=-12?