How do you find the x and y intercepts of $3 x - 4 y = - 12$ $3x-4y=-12$ ?

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Answer 1 · 2017-07-09T22:11:13

$(0, 3) and (- 4, 0)$ $(0,3) and (-4, 0)$

$3 \cdot 0 - 4 y = - 12 \Rightarrow y = 3 \Rightarrow (0, 3) \in r$ $3*0 -4y = -12 => y = 3 => (0,3) in r$

$3 x - 4 \cdot 0 = - 12 \Rightarrow x = - 4 \Rightarrow (- 4, 0) \in r$ $3x -4 * 0 = -12 => x = -4 => (-4, 0) in r$

How do you find the x and y intercepts of 3x-4y=-123x−4y=−123x-4y=-12?