How do you find the x and y intercepts of -4x=8y+12−4x=8y+12?

2 Answers
NickTheTurtle
Mar 29, 2017

x-intercept: (-3, 0)(−3,0)
y-intercept: (0, -3/2)(0,−32)

Explanation:

The x-intercept occurs when the line crosses the x-axis. If you think about it, this point occurs when y=0y=0.

-4x=8*0+12=12−4x=8⋅0+12=12 {substituted y=0y=0}
x=-3x=−3

When y=0y=0, x=-3x=−3. The x-intercept is therefore (-3, 0)(−3,0).

The y-intercept occurs when the line crosses the y-axis. As above, this point occurs when x=0x=0.

-4*0=8y+12−4⋅0=8y+12 {substituted x=0x=0}
y=-12/8=-3/2y=−128=−32

When x=0x=0, y=-3/2y=−32. The y-intercept is therefore (0, -3/2)(0,−32).

Jim G.
Mar 29, 2017

"y-intercept "=-3/2," x-intercept "=-3y-intercept =−32, x-intercept =−3

Explanation:

To find the color(blue)"x and y intercepts"x and y intercepts

• " let x = 0, in the equation, for y-intercept"∙ let x = 0, in the equation, for y-intercept

• " let y = 0, in the equation, for x-intercept"∙ let y = 0, in the equation, for x-intercept

x=0to8y+12=0to8y=-12toy=-3/2x=0→8y+12=0→8y=−12→y=−32

y=0to-4x=0+12to-4x=12tox=-3y=0→−4x=0+12→−4x=12→x=−3
graph{-1/2x-3/2 [-10, 10, -5, 5]}

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