How do you find the x and y intercepts of $4y=16$ ?

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Answer 1 · 2017-02-01T11:33:14

See the entire solution process below:

First, solve this equation for $y$ :

$(4y)/color(red)(4) = 16/color(red)(4)$

$(color(red)(cancel(color(black)(4)))y)/cancel(color(red)(4)) = 4$

$y = 4$

Because there is no $x$ term we know this is a horizontal line where for every value of $x$ $y$ is equal to $4$ .

Therefore, the y-intercept is $4$ or $(0, 4)$

Also, because this is a horizontal line there is no x-intercept.

How do you find the x and y intercepts of 4y=164y=16?