How do you find the x and y intercepts of $6 x + 2 y = 10$ $6x+2y=10$ ?

Question

2677 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-07T13:31:55

The intercepts are at $(1 \frac{2}{3}, 0) and (0, 5)$ $(1 2/3, 0) and (0, 5)$

Leave the equation $6 x + 2 y = 10$ $6x +2y = 10$ in this form.

All along the $x -$ $x-$ axis, $y = 0$ $y=0" "$ All along the $y -$ $y-$ axis, $x = 0$ $x=0$

To find the $y -$ $y-$ intercept, set $x = 0$ $x=0$

$6 (0) + 2 y = 10 \to y = 5$ $6(0) + 2y = 10" "rarr y = 5$

To find the $x -$ $x-$ intercept, set $y = 0$ $y=0$

$6 x + 2 (0) = 10 \to x = \frac{10}{6} = \frac{5}{3} = 1 \frac{2}{3}$ $6x + 2(0) = 10" " rarr x = 10/6 = 5/3 = 1 2/3$

The intercepts are at $(1 \frac{2}{3}, 0) and (0, 5)$ $(1 2/3, 0) and (0, 5)$

How do you find the x and y intercepts of 6x+2y=106x+2y=10?