How do you find the x- and y-intercepts of $-6x-2y=3$ ?

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Answer 1 · 2016-12-13T14:24:20

The x-intercept is $x = -1/2$ or $(-1/2, 0)$

The y-intercept is $y = -3/2$ or $(0, -3/2)$

To find the $x$ intercept for this line substitute $0$ for $y$ and solve for $x$ :

$-6x - (2*0) = 3$

$-6x - 0 = 3$

$-6x = 3$

$(-6x)/-6 = 3/-6$

$(cancel(-6)x)/cancel(-6) = -1/2$

$x = -1/2$

To find the $y$ intercept for this line substitute $0$ for $x$ and solve for $y$ :

$(-6*0) - 2y = 3$

$0 - 2y = 3$

$-2y = 3$

$(-2y)/-2 = 3/-2$

$(cancel(-2)y)/cancel(-2) = -3/2$

$y = -3/2$

How do you find the x- and y-intercepts of -6x-2y=3-6x-2y=3?