How do you find the x and y intercepts of $- 6 x + 8 y = - 36$ $-6x+8y=-36$ ?

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Answer 1 · 2017-04-04T12:29:57

See the entire solution process below:

To find the y-intercept, set $x$ $x$ to $0$ $0$ and solve for $y$ $y$ :

$(- 6 \times 0) + 8 y = - 36$ $(-6 xx 0) + 8y = -36$

$0 + 8 y = - 36$ $0 + 8y = -36$

$8 y = - 36$ $8y = -36$

$\frac{8 y}{8} = - \frac{36}{8}$ $(8y)/color(red)(8) = -36/color(red)(8)$

$(color(red)(cancel(color(black)(8)))y)/cancel(color(red)(8)) = (4 xx -9)/color(red)(4 xx 2)$

$y = (color(red)(cancel(color(black)(4))) xx -9)/color(red)(color(black)(cancel(color(red)(4))) xx 2)$

$y = -9/2$

The y-intercept is $-9/2$ or $(0, -9/2)$

To find the x-intercept, set $y$ to $0$ and solve for $x$ :

$-6x + (8 xx 0) = -36$

$-6x + 0 = -36$

$-6x = -36$

$(-6x)/color(red)(-6) = (-36)/color(red)(-6)$

$(color(red)(cancel(color(black)(-6)))x)/cancel(color(red)(-6)) = 6$

$x = 6$

The x-intercept is $6$ or $(6, 0)$

How do you find the x and y intercepts of -6x+8y=-36−6x+8y=−36-6x+8y=-36?