How do you find the x and y intercepts of $6 y = 3 x + 6$ $6y=3x+6$ ?

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Answer 1 · 2018-03-06T14:14:19

$x$ $x$ -intercept is $- 2$ $-2$ and $y$ $y$ -intercept is $1$ $1$

To find $x$ $x$ -intercept of any line (actually, I should say any curve) just put $y = 0$ $y=0$

and to $x$ $x$ -intercept of any line (again any curve) just put $x = 0$ $x=0$ .

Hence $x$ $x$ -intercept of $6 y = 3 x + 6$ $6y=3x+6$ is given by $6 \cdot 0 = 3 x + 6$ $6*0=3x+6$ or $3 x = - 6$ $3x=-6$ i.e. $x = - 2$ $x=-2$

and $y$ $y$ -intercept of $6 y = 3 x + 6$ $6y=3x+6$ is given by $6 y = 3 \cdot 0 + 6$ $6y=3*0+6$ or $6 y = 6$ $6y=6$ i.e. $y = 1$ $y=1$ .

graph{6y=3x+6 [-2.958, 2.042, -1, 1.5]}

How do you find the x and y intercepts of 6y=3x+66y=3x+66y=3x+6?