How do you find the x and y intercepts of $8 y - 5 = 3 x$ $8y-5=3x$ ?

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Answer 1 · 2017-01-18T15:59:16

See the entire solution process below:

To find the x-intercept we set $y$ $color(red)(y)$ to $0$ $color(red)(0)$ and solve for $x$ $x$ :

$8 y - 5 = 3 x$ $8color(red)(y) - 5 = 3x$ becomes:

$(8 \times 0) - 5 = 3 x$ $(8 xx color(red)(0)) - 5 = 3x$

$0 - 5 = 3 x$ $0 - 5 = 3x$

$- 5 = 3 x$ $-5 = 3x$

$- \frac{5}{3} = \frac{3 x}{3}$ $-5/color(red)(3) = (3x)/color(red)(3)$

$- \frac{5}{3} = x$ $-5/3 = x$

$x = - \frac{5}{3}$ $x = -5/3$

To find the y-intercept we set $x$ $color(red)(x)$ to $0$ $color(red)(0)$ and solve for $y$ $y$ :

$8 y - 5 = 3 x$ $8y - 5 = 3color(red)(x)$ becomes:

$8 y - 5 = (3 \times 0)$ $8y - 5 = (3 xx color(red)(0))$

$8 y - 5 = 0$ $8y - 5 = 0$

$8 y - 5 + 5 = 0 + 5$ $8y - 5 + color(red)(5) = 0 + color(red)(5)$

$8 y - 0 = 5$ $8y - 0 = 5$

$\frac{8 y}{8} = \frac{5}{8}$ $(8y)/color(red)(8) = 5/color(red)(8)$

$(color(red)(cancel(color(black)(8)))y)/cancel(color(red)(8)) = 5/8$

$y = 5/8$

The x-intercept is $-5/3$ or $(-5/3, 0)$

The y-intercept is $5/8$ or $(0, 5/8)$

How do you find the x and y intercepts of 8y-5=3x8y−5=3x8y-5=3x?