How do you find the x and y intercepts of $x + 3 y = - 1$ $x+3y=-1$ ?

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Answer 1 · 2016-12-09T18:52:54

$x-intercept =-1$ $"x-intercept =-1"$

$y-intercept=-0.33$ $"y-intercept=-0.33"$

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$let's write x=0 for y-intercept$ $"let's write x=0 for y-intercept"$

$0 + 3 y = - 1$ $0+3y=-1$

$y = - \frac{1}{3}$ $y=-1/3$

$y = - 0.33$ $y=-0.33$

$let's write y=0 for x-intercept$ $"let's write y=0 for x-intercept"$

$x + 3 \cdot 0 = - 1$ $x+3*0=-1$

$x + 0 = - 1$ $x+0=-1$

$x = - 1$ $x=-1$

How do you find the x and y intercepts of x+3y=−1x+3y=-1?