How do you find the x and y intercepts of $y = - 2$ $y=-2$ ?

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Answer 1 · 2017-08-21T01:14:30

See a solution process below:

The equation $y = - 2$ $y = -2$ defines a horizontal line where for each and every value of $x$ $x$ , $y$ $y$ is equal to $- 2$ $-2$ .

So, for $x = 0$ $x = 0$ , $y = - 2$ $y = -2$ Therefore the $y$ $y$ -intercept is $(0, - 2)$ $(0, -2)$

Because this is a horizontal line parallel to the $x$ $x$ access at a point of $- 2$ $-2$ on the $y$ $y$ -axis, there is no $x$ $x$ -intercept.

How do you find the x and y intercepts of y=-2y=−2y=-2?