How do you find the x and y intercepts of $y = \frac{2}{3} x - 4$ $y=2/3x-4$ ?

Question

5074 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-01T15:24:21

See the entire solution process below:

To find the y-intercept by substitution, substitute $0$ $0$ for $x$ $x$ and calculate $y$ $y$ :

$y = (\frac{2}{3} \times 0) - 4$ $y = (2/3 xx 0) - 4$

$y = 0 - 4$ $y = 0 - 4$

$y = - 4$ $y = -4$ Therefore the y-intercept is $- 4$ $-4$ or $(0, - 4)$ $(0, -4)$

To find the x-intercept by substitution, substitute $0$ $0$ for $y$ $y$ and solve for $x$ $x$ :

$0 = \frac{2}{3} x - 4$ $0 = 2/3x - 4$

$0 + 4 = \frac{2}{3} x - 4 + 4$ $0 + color(red)(4) = 2/3x - 4 + color(red)(4)$

$4 = \frac{2}{3} x - 0$ $4 = 2/3x - 0$

$4 = \frac{2}{3} x$ $4 = 2/3x$

$\frac{3}{2} \times 4 = \frac{3}{2} \times \frac{2}{3} x$ $color(red)(3)/color(blue)(2) xx 4 = color(red)(3)/color(blue)(2) xx 2/3x$

$12/color(blue)(2) = cancel(color(red)(3))/cancel(color(blue)(2)) xx color(blue)(cancel(color(black)(2)))/color(red)(cancel(color(black)(3)))x$

$6 = x$

$x = 6$ Therefore the x-intercept is $6$ or $(6, 0)$

How do you find the x and y intercepts of y=2/3x-4y=23x−4y=2/3x-4?