How do you find the x and y intercepts of y=3x−2?

2 Answers
Jim G.
Apr 19, 2018

x-intercept =23, y-intercept =−2

Explanation:

To find the intercepts, that is where the graph crosses
the x and y axes

∙ let x = 0, in the equation for y-intercept

∙ let y = 0, in the equation for x-intercept

x=0⇒y=0−2=−2←y-intercept

y=0⇒3x−2=0⇒x=23←x-intercept
graph{(y-3x+2)((x-0)^2+(y+2)^2-0.04)((x-2/3)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}

James M.
Apr 19, 2018

y-intercept =(0,−2)or−2
y-intercept =(23,0)or23

Explanation:

The y-intercept is when the value of x=0. Therefore, plugging in the value of x into the equation:

3(0)−2=−2 So, y=−2 This is for the y-intercept

The x intercept is when y=0, substituting this into the equation gives us:

0=3x−2 It is possible to rearrange this:

0−3x=3x−3x−2
3x=2
x=23

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