How do you find the x and y intercepts of $y = 4 x - 2$ $y=4x-2$ ?

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Answer 1 · 2017-01-31T01:41:47

See the entire explanation below:

Because this equation is in the slope-intercept form you can obtain the y-intercept directly from the equation.

The slope-intercept form of a linear equation is:

$y = m x + b$ $y = color(red)(m)x + color(blue)(b)$

or in this case:

$y = 4 x - 2$ $y = color(red)(4)x - color(blue)(2)$

Where $m$ $color(red)(m)$ is the slope and $b$ $color(blue)(b)$ is the y-intercept value.

Therefore the y-intercept is $- 2$ $-2$ or $(0, - 2)$ $(0, -2)$

To find the x-intercept we set $y$ $y$ equal to $0$ $0$ and solve for $x$ $x$ :

$0 = 4 x - 2$ $0 = 4x - 2$

$0 + 2 = 4 x - 2 + 2$ $0 + 2 = 4x - 2 + 2$

$2 = 4 x - 0$ $2 = 4x - 0$

$2 = 4 x$ $2 = 4x$

$\frac{2}{4} = \frac{4 x}{4}$ $2/4 = (4x)/4$

$1/2 = (cancel(4)x)/cancel(4)$

$1/2 = x$ or $x = 1/2$

Therefore the x-intercept is $1/2$ or $(1/2, 0)$

How do you find the x and y intercepts of y=4x-2y=4x−2y=4x-2?