How do you find the x- and y-intercepts of $y=-7x-3$ ?

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Answer 1 · 2016-12-11T23:58:02

The x- and y-intercepts are (0, -3) and ( $-3/7$ , 0)

The $y$ -intercept is where $x = 0$ . Substituting $0$ for $x$ in the equation and solving for $y$ gives:

$y = (-7 xx 0) - 3$

$y = 0 - 3$

#y = -3

So, the y-intercept with x = 0 and y = -3 is: (0, -3)

The $x$ -intercept is where $y = 0$ . Substituting $0$ for $y$ in the equation and solving for $x$ gives:

$0 = -7x - 3$

$0 + 3 = -7x - 3 + 3$

$3 = -7x - 0$

$3 = -7x$

$3/-7 = (-7x)/-7$

$-3/7 = (cancel(-7)x)/cancel(-7)$

$x = -3/7$

So, the x-intercept with y = 0 and x = -3/7 is: ( $-3/7$ , 0)

How do you find the x- and y-intercepts of y=-7x-3y=-7x-3?