How do you find the x and y intercepts of $y = - x + 1$ $y=-x+1$ ?

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Answer 1 · 2017-02-08T00:20:39

See the solution process below:

The slope-intercept form of a linear equation is: $y = m x + b$ $y = color(red)(m)x + color(blue)(b)$

Where $m$ $color(red)(m)$ is the slope and $b$ $color(blue)(b)$ is the y-intercept value.

This equation is in the slope intercept form ( $y = - 1 x + 1$ $y = color(red)(-1)x + color(blue)(1)$ )

The y-intercept is $b = 1$ $color(blue)(b = 1)$ or $(0, 1)$ $(0, 1)$

To find the x-intercept set $y$ $y$ to $0$ $0$ and solve for $x$ $x$ :

$0 = - 1 x + 1$ $0 = color(red)(-1)x + color(blue)(1)$

$0 - 1 = - 1 x + 1 - 1$ $0 - 1 = color(red)(-1)x + color(blue)(1) - 1$

$- 1 = - 1 x + 0$ $-1 = color(red)(-1)x + 0$

$- 1 = - 1 x$ $-1 = color(red)(-1)x$

$- 1 \times - 1 = - 1 \times - 1 x$ $color(blue)(-1) xx -1 = color(blue)(-1) xx color(red)(-1)x$

$1 = 1 x$ $1 = 1x$

$x = 1$ $x = 1$

The x-intercept is $1$ $1$ or $(1, 0)$ $(1, 0)$

How do you find the x and y intercepts of y=−x+1y=-x+1?