How do you find the x intercept for f(x)=2log4(x)f(x)=2log4(x)?

1 Answer
Dec 17, 2015

Solve for xx in f(x) = 0f(x)=0 to find that the xx intercept occurs at
x = 1x=1.

Explanation:

An xx-intercept occurs where f(x) = 0f(x)=0, and so to find any xx-intercepts, we simply solve for xx in that equation.

We will be proceeding under the assumption that the question is regarding the base-44 log of xx (as opposed to the base 1010 or base ee log of 4x4x).

Using the property that a^(log_a(x)) = xaloga(x)=x we get

2log_4(x) = 02log4(x)=0

=> log_4(x) = 0log4(x)=0

=> 4^(log_4(x)) = 4^04log4(x)=40

=> x = 1x=1