How do you find the x intercept of 4x-3y=12?

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Answer 1 · 2016-08-31T09:40:24

$x = 3$ $x=3$

$x$ $x$ - intercept of the equation $4 x - 3 y = 12$ $4x-3y=12$ can be found by plugging $y = 0$ $y=0$
So we get

$4 x - 3 \times 0 = 12$ $4x-3times0=12$

or

$4 x - 0 = 12$ $4x-0=12$

or

$4 x = 12$ $4x=12$

or

$x = \frac{12}{4}$ $x=12/4$

or

$x = 3$ $x=3$