How do you find the x & y intercept for 5x+3y=30?

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Answer 1 · 2016-08-06T00:04:43

The x-intercept is + 6 and the y-intercept is + 10

$(6, 0)$ $(6,0)$ and $(0, 10)$ $(0,10)$

The $x$ $x$ -intercept is the value for $x$ $x$ when $y = 0$ $y=0$ , and
the $y$ $y$ - intercept is the value of $y$ $y$ when $x = 0$ $x=0$ .

Replace each variable in turn with 0 and solve.

$5 x + 3 y = 30$ $5x + 3y = 30$ Put zero in place of x and solve for y

$5 (0) + 3 y = 30$ $5(0) + 3y = 30$

$\frac{3 y}{3}$ $(3y)/3$ = $\frac{30}{3}$ $30/3$

$y = 10$ $y = 10$ The y intercept is + 10

$5 x + 3 y = 30$ $5x + 3y = 30$ Put zero in place of y and solve for x

$5 x + 3 (0) = 30$ $5x + 3(0) = 30$

$\frac{5 x}{5} = \frac{30}{5}$ $(5x)/5 = 30/5$

$x = 6$ $x = 6$ The x intercept is + 6