How do you find the y intercept given #y=-1/6x+6#?

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Answer 1 · 2018-08-02T01:01:41

The #y#-intercept is at (0, 6).

#y = -1/6x + 6#

To find the #y#-intercept, plug in #0# for #x# and solve for #y#:
#y = -1/6(0) + 6#

#y = 0 + 6#

#y = 6#

Therefore, the #y#-intercept is at #(0, 6)#.

Hope this helps!

Answer 2 · 2018-08-02T01:33:17

#6#

#y-mx+b#, with slope #m# and a #y#-intercept of #b#.

By pattern matching, we see that our #b# term, the #y#-intercept, is #6#.

Hope this helps!