How do you find the zeros of #f(x)=(x+2)/(x^2-6x+8)#? Algebra Rational Equations and Functions Graphs of Rational Functions 1 Answer t0hierry Jan 20, 2017 #x=-2# Explanation: #x = -2# makes the numerator zero, while not making the denominator zero. Answer link Related questions What are Rational Functions? Why do Rational functions have asymptotes? How do you graph rational functions? What are asymptotes? How do you find points of discontinuity in rational functions? How do you find the points of discontinuity and the asymptote for the function #y=6/(x-5)#? How do you identify the vertical and horizontal asymptotes for rational functions? How do you graph #y=\frac{x}{2-x^2}-3#? How do you find the x intercept of #f(x) = (x^2+9x)/(x^2+3x-4)#? How do you graph the rational function #f(x)=6/(x^2+x-2)#? See all questions in Graphs of Rational Functions Impact of this question 2069 views around the world You can reuse this answer Creative Commons License