Question

How do you find three consecutive odd integers whose sum of the second and third integers is three less then three times the first integer?

Answer 1

Consider `n`, `n+1` and `n+2`, three consecutive integers. See explanation below

Explanation:

`n`, `n+1` and `n+2`. then `n+1+n+2+3=3n`

`2n+6=3n`

`3n-2n=6`

`n=6` is the first integer and `7` and `8` the second and third