How do you find two consecutive integers whose sum is 211?

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How do you find two consecutive integers whose sum is 211?

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Answer 1 · 2017-07-22T18:11:13

$105 and 106$ $105" and " 106$

Explanation:

$integers are 1 unit apart$ $"integers are 1 unit apart"$

$let n be an integer then a consecutive integer is n + 1$ $"let n be an integer then a consecutive integer is n + 1"$

$\Rightarrow n + (n + 1) = 211 \leftarrow solve for n$ $rArrn+(n+1)=211larr" solve for n"$

$\Rightarrow 2 n + 1 = 211$ $rArr2n+1=211$

$subtract 1 from both sides$ $"subtract 1 from both sides"$

$2ncancel(+1)cancel(-1)=211-1$

$rArr2n=210$

$"divide both sides by 2"$

$(cancel(2) n)/cancel(2)=210/2$

$rArrn=105" and " n+1=105+1=106$

$"thus the 2 consecutive integers are " 105" and "106$

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How do you find two consecutive integers whose sum is 211?

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