How do you find two difference parametric equations for the rectangular equation y=8x-7?

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Answer 1 · 2018-07-28T17:08:00

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Given equation:

#y=8x-7#

Parametric equation 1: Let #x=t# then

#y=8t-7#

hence the parametric will be #x=t, \ y=8t-7#

Parametric equation 2: Let #x=r\cos\theta# & #y=r\sin\theta# then

#r\sin\theta=8r\cos\theta-7#

#r(8\cos\theta-\sin\theta)=7#

#r=7/(8\cos\theta-\sin\theta)#