How do you find vertical, horizontal and oblique asymptotes for $f (x) = \frac{x^{3} + 1}{x + 1}$ $f(x)= (x^3+1 )/( x+1)$ ?

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Answer 1 · 2016-07-04T18:19:32

$f (x) = \frac{x^{3} + 1}{x + 1} = 1 - x + x^{2}$ $f(x)= (x^3+1 )/( x+1) = 1 - x + x^2$

so no asymptotes

How do you find vertical, horizontal and oblique asymptotes for f(x)= (x^3+1 )/( x+1)f(x)=x3+1x+1 f(x)= (x^3+1 )/( x+1)?