How do you find vertical, horizontal and oblique asymptotes for ( x^2 - 1)/(x)x2−1x?
1 Answer
vertical asymptote x = 0
oblique asymptote y = x
Explanation:
Vertical asymptotes occur as the denominator of a rational function tends to zero. To find the equation set the denominator equal to zero.
rArr x = 0 " is the asymptote " ⇒x=0 is the asymptote Horizontal asymptotes occur if the degree of the numerator ≤ degree of the denominator. This is not the case here hence there are no horizontal asymptotes.
Oblique asymptotes occur when the degree of the numerator > degree of the denominator. This is the case here hence there is an oblique asymptote.
To find equation divide numerator by denominator.
rArr (x^2 - 1)/x = x^2/x - 1/x = x - 1/x⇒x2−1x=x2x−1x=x−1x as
x to+-oo , 1/x to 0" and " y to x x→±∞,1x→0 and y→x
rArr y = x " is the asymptote " ⇒y=x is the asymptote
graph{(x^2-1)/x [-10, 10, -5, 5]}