How do you find vertical, horizontal and oblique asymptotes for (x^2 - 2x + 3) / xx22x+3x?

1 Answer
Jun 8, 2016

Vertical asymptotes:

Vertical asymptotes occur when the denominator of a rational function equals to 0 (this being because division by 0 is undefined in mathematics). We can find any vertical asymptotes by setting the denominator to 0 and solving.

x = 0x=0

x = 0x=0

There will be a vertical asymptote at x = 0x=0

Horizontal asymptotes:

Horizontal asymptotes only occur when the degree of the denominator is higher or equal to that of the numerator. We don't have this situation in our function.

Oblique asymptotes:

Oblique asymptotes occur when the denominator has a lower degree than the numerator. If the function is f(x) = (g(x))/(h(x))f(x)=g(x)h(x), there will be an oblique asymptote at the quotient of g(x)/ (h(x))g(x)h(x).

Therefore, we will have to divide your rational function. A thorough understanding of division of polynomials is usually a pre-requisite to finding oblique asymptotes.

By synthetic division:

"0_| 1 -2 3"0_| 1 -2 3
" 0 0 0" 0 0 0
"---------------"---------------
" 1 -2 3" 1 -2 3

The quotient is therefore x - 2x2, with the remainder being 33.

There will therefore be an oblique asymptote at y = x - 2y=x2

Here is the graph of the function:

enter image source here

Hopefully this helps!