Question

How do you find vertical, horizontal and oblique asymptotes for `(x^2 + 5x + 6)/(x+3)`?

Answer 1

`"no asymptotes"`

Explanation:

`"factor the numerator"`

`=((x+2)cancel((x+3)))/cancel((x+3))=x+2`

`"the removal of the factor "(x+3)" indicates a removable"`
`"discontinuity (hole) at "x=-3`

`"The simplified version is a linear equation with "`
`"no asymptotes"`
graph{(x^2+5x+6)/(x+3) [-10, 10, -5, 5]}