How do you find $w (- 1)$ $w(-1)$ given $w (x) = x^{3} - 2$ $w(x)=x^3-2$ ?

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How do you find $w (- 1)$ $w(-1)$ given $w (x) = x^{3} - 2$ $w(x)=x^3-2$ ?

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Answer 1 · 2016-10-01T07:31:22

$w (- 1) = - 3$ $w(-1)=-3$

Explanation:

$w (x) = x^{3} - 2$ $w(x)=x^3-2$ means $w$ $w$ is a function of $x$ $x$ . To find the value of $w (x)$ $w(x)$ at any given value of $x$ $x$ , we just substitute $x$ $x$ in the function. Hence

$w (- 1) = {(- 1)}^{3} - 2$ $w(-1)=(-1)^3-2$

= $- 1 - 2$ $-1-2$

= $- 3$ $-3$

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How do you find $w (- 1)$ $w(-1)$ given $w (x) = x^{3} - 2$ $w(x)=x^3-2$ ?

1 Answer

Explanation:

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How do you find $w (- 1)$ $w(-1)$ given $w (x) = x^{3} - 2$ $w(x)=x^3-2$ ?