How do you find $w (2)$ $w(2)$ given $w (x) = 4 x - 1$ $w(x)=4x-1$ ?

Question

2458 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-12T14:18:49

See the entire solution process below:

To solve this we must substitute $2$ $color(red)(2)$ for every occurrence of $x$ $color(red)(x)$ in the function:

$w (x) = 4 x - 1$ $w(color(red)(x)) = 4color(red)(x) - 1$ becomes:

$w (2) = (4 \times 2) - 1$ $w(color(red)(2)) = (4 xx color(red)(2)) - 1$

$w (2) = 8 - 1$ $w(color(red)(2)) = 8 - 1$

$w (2) = 7$ $w(color(red)(2)) = 7$

How do you find w(2)w(2)w(2) given w(x)=4x-1w(x)=4x−1w(x)=4x-1?