How do you find $w (7)$ $w(7)$ given $w (a) = - a^{2} + 5 a$ $w(a)=-a^2+5a$ ?

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Answer 1 · 2016-08-08T14:00:15

$= - 14$ $=-14$

$w (a) = - a^{2} + 5 a$ $w(a)=-a^2+5a$
or
$w (7) = - {(7)}^{2} + 5 (7)$ $w(7)=-(7)^2+5(7)$
$= - 49 + 35$ $=-49+35$
$= - 14$ $=-14$

How do you find w(7)w(7) given w(a)=−a2+5aw(a)=-a^2+5a?