How do you find x and y intercepts of $- 3 x + y = 6$ $-3x + y = 6$ ?

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Answer 1 · 2017-02-20T19:12:57

$x - intercept = (- 2, 0)$ $x-"intercept" = (-2,0)$

$y - intercept = (0, 6)$ $y-"intercept" = (0,6)$

All along the $x$ $x$ -axis, the $y$ $y$ -value is zero.

All along the $y$ $y$ -axis, the $x$ $x$ -value is zero.

TO find the $x$ $x$ -intercept make $y = 0$ $y=0$

$- 3 x + y = 6$ $-3x +y =6$

$- 3 x + 0 = 6$ $-3x +0 =6$

$x = - 2 \to the point is (- 2, 0)$ $x = -2" "rarr" the point is " (-2,0)$

TO find the $y$ $y$ -intercept make $x = 0$ $x=0$

$- 3 x + y = 6$ $-3x +y = 6$

$0 + y = 6$ $0 +y =6$

$y = 6 \to the point is (0, 6)$ $y=6" "rarr" the point is " (0,6)$

How do you find x and y intercepts of −3x+y=6 -3x + y = 6?