How do you find x and y intercepts of $- 5 x + 6 y = 30$ $-5x + 6y = 30$ ?

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Answer 1 · 2017-04-08T02:25:43

See the entire solution process below:

To find the y-intercept, set $x = 0$ $x = 0$ and solve for $y$ $y$ :

$- 5 x + 6 y = 30$ $-5x + 6y = 30$ becomes:

$(- 5 \times 0) + 6 y = 30$ $(-5 xx 0) + 6y = 30$

$0 + 6 y = 30$ $0 + 6y = 30$

$6 y = 30$ $6y = 30$

$\frac{6 y}{6} = \frac{30}{6}$ $(6y)/color(red)(6) = 30/color(red)(6)$

$(color(red)(cancel(color(black)(6)))y)/cancel(color(red)(6)) = 5$

$y = 5$

The y-intercept is $y = 5$ or $(0, 5)$

To find the x-intercept, set $y = 0$ and solve for $x$ :

$-5x + 6y = 30$ becomes:

$-5x + (6 xx 0) = 30$

$-5x + 0 = 30$

$-5x = 30$

$(-5x)/color(red)(-5) = 30/color(red)(-5)$

$(color(red)(cancel(color(black)(-5)))x)/cancel(color(red)(-5)) = -6$

$x = -6$

The x-intercept is $x = -6$ or $(-6, 0)$

How do you find x and y intercepts of -5x + 6y = 30−5x+6y=30 -5x + 6y = 30?