How do you find x and y intercepts of $x + 2 y - 8$ $x+2y-8$ ?

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How do you find x and y intercepts of $x + 2 y - 8$ $x+2y-8$ ?

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Answer 1 · 2018-02-01T14:14:53

$x = 8 and y = 4$ $x=8" and "y=4$

Explanation:

$this is the general equation of a straight line but should$ $"this is the general equation of a straight line but should"$
$be equal to zero$ $"be equal to zero"$

$∙ x A x + B y + C = 0 \leftarrow general form$ $•color(white)(x)Ax+By+C=0larrcolor(blue)"general form"$

$\Rightarrow x + 2 y - 8 = 0$ $rArrx+2y-8=0$

$to find the x and y intercepts$ $"to find the x and y intercepts "$

$∙ let x = 0, in the equation for y-intercept$ $• " let x = 0, in the equation for y-intercept"$

$∙ let y = 0, in the equation for x-intercept$ $• " let y = 0, in the equation for x-intercept"$

$x = 0 \to 0 + 2 y = 8 \Rightarrow y = 4 \leftarrow y-intercept$ $x=0to0+2y=8rArry=4larrcolor(red)"y-intercept"$

$y = 0 \to x + 0 = 8 \Rightarrow x = 8 \leftarrow x-intercept$ $y=0tox+0=8rArrx=8larrcolor(red)"x-intercept"$
graph{y+1/2x-4=0 [-10, 10, -5, 5]}

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How do you find x and y intercepts of $x + 2 y - 8$ $x+2y-8$ ?

1 Answer

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How do you find x and y intercepts of $x + 2 y - 8$ $x+2y-8$ ?