How do you find x given (2,4), (x,8) and slope is -2?

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How do you find x given (2,4), (x,8) and slope is -2?

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Answer 1 · 2017-01-05T05:10:02

$x = 0$ $x=0$

Explanation:

$\frac{y_{2} - y_{1}}{x_{2} - x_{1}} = m$ $(y_2-y_1)/(x_2-x_1)=m$

$x_{1} = 2$ $x_1=2$
$x_{2} = x$ $x_2=x$
$y_{1} = 4$ $y_1=4$
$y_{2} = 8$ $y_2=8$

$\frac{8 - 4}{x - 2} = - 2$ $(8-4)/(x-2)=-2$

$\frac{4}{x - 2} = - 2$ $4/(x-2)=-2$
$\frac{1}{x - 2} = - \frac{2}{4} = - 2$ $1/(x-2)=-2/4=-2$
Reciprocate both sides
$\frac{x - 2}{1} = - \frac{1}{2}$ $(x-2)/1=-1/2$
$x - 2 = - 2$ $x-2=-2$
$x = - 2 + 2 = 0$ $x=-2+2=0$
$x = 0$ $x=0$

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How do you find x given (2,4), (x,8) and slope is -2?

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