How do you find x when y= -2, -1, 0 and 1 given 4(5-y)=14x+34(5−y)=14x+3?

1 Answer
Mahek ☮
Mar 29, 2018

See below for a detailed solution:

Explanation:

color(green)(4(5-y)=14x+34(5−y)=14x+3

=20-4y=14x+3=20−4y=14x+3

14x=20-4y-314x=20−4y−3

14x=17-4y14x=17−4y

color(red)(x=(17-4y)/14x=17−4y14

Part 1 - When color(blue)(y=-2y=−2

x=(17-4y)/14x=17−4y14

x=(17-4xx-2)/14x=17−4×−214

x=(17+8)/14x=17+814

color(magenta)(x=25/14=1 11/14x=2514=11114

Part 2- When color(blue)(y=-1y=−1

x=(17-4y)/14x=17−4y14

x=(17-4xx-1)/14x=17−4×−114

x=(17+4)/14x=17+414

color(magenta)(x=21/14 =3/2=1 1/2x=2114=32=112

Part 3 - When color(blue)(y=0y=0

x=(17-4y)/14x=17−4y14

x=(17-4xx0)/14x=17−4×014

x=(17+0)/14x=17+014

color(magenta)(x=17/14=1 3/14x=1714=1314

Part 4 - When color(blue)(y=1y=1

x=(17-4y)/14x=17−4y14

x=(17-4xx1)/14x=17−4×114

x=(17-4)/14x=17−414

color(magenta)(x=13/14x=1314

~Hope this helps! :)

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