Question

How do you find x when y= -2, -1, 0 and 1 given `4(5-y)=14x+3`?

Answer 1

See below for a detailed solution:

Explanation:

`color(green)(4(5-y)=14x+3`

`=20-4y=14x+3`

`14x=20-4y-3`

`14x=17-4y`

`color(red)(x=(17-4y)/14`

Part 1 - When `color(blue)(y=-2`

`x=(17-4y)/14`

`x=(17-4xx-2)/14`

`x=(17+8)/14`

`color(magenta)(x=25/14=1 11/14`

Part 2- When `color(blue)(y=-1`

`x=(17-4y)/14`

`x=(17-4xx-1)/14`

`x=(17+4)/14`

`color(magenta)(x=21/14 =3/2=1 1/2`

Part 3 - When `color(blue)(y=0`

`x=(17-4y)/14`

`x=(17-4xx0)/14`

`x=(17+0)/14`

`color(magenta)(x=17/14=1 3/14`

Part 4 - When `color(blue)(y=1`

`x=(17-4y)/14`

`x=(17-4xx1)/14`

`x=(17-4)/14`

`color(magenta)(x=13/14`

~Hope this helps! :)