Question

How do you find zeros of `g(x)=12x^3-2x^2-2x`?

Answer 1

You can separate one `x` to reduce it to a second degree equation

Explanation:

`g(x)=12x^3−2x^2−2x = x*(12x^2−2x−2)`

so `g(x) = 0` when either `x = 0` or `12x^2−2x−2 = 0`.