How do you generalize Delta(PV) from d(PV)?

I thought this was cool when I found it in my book---it is indeed a common error to make!

1 Answer
Dec 21, 2017

In fact, it is not that obvious. Oftentimes when we see a differential like d(PV), we might go to the product rule:

d(PV) = PdV + VdP

which is fine for differentials. With Delta changes though, it is not quite that simple. In other words,

Delta(PV) ne P_1DeltaV + V_1DeltaP.

The way my book does it (Physical Chemistry, Levine, pg. 52) is quite ingenious, actually. By definition:

Delta(PV) = P_2V_2 - P_1V_1

But here is a way to prove what Delta(PV) actually is. For any size of Delta,

Delta(PV) = P_2V_2 - P_1V_1

= (P_2 - P_1 + P_1)(V_2 - V_1 + V_1) - P_1V_1

= (P_1 + DeltaP)(V_1 + DeltaV) - P_1V_1

Distribute to get:

= cancel(P_1V_1) + P_1DeltaV + V_1DeltaP + DeltaPDeltaV cancel(- P_1V_1)

Therefore, for any size of Delta:

color(blue)(barul|stackrel(" ")(" "Delta(PV) = P_1DeltaV + V_1DeltaP + DeltaPDeltaV" ")|)

For differentials we do not have to worry about this because the product of two differentials is small, i.e. dPdV ~~ 0. But when the change is not small, DeltaPDeltaV is also not small.